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how do I factor 8x^2+21=-59x
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First add 59x to the other side so that 8x^2 + 59x + 21 = 0 Then find factors that multiply to 168 and add up to 59. Do you know how to do the rest?
The factors are 56 and 3. Reinsert them in the place of 59: 8x^2 + 56x+ 3x + 21 = 0. Now group the first 2 terms together and group the second 2 terms together by placing parentheses around them. (8x^2 + 56x) + (3x + 21) = 0 Now factor out the GCF separately in both binomials. 8x(x + 7) + 3(x + 7). Now combine the numbers outside the parentheses and the numbers inside separately. The final answer is (8x + 3)(x + 7)
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