Question

solve the inequality and specify the answer using interval notation 9/10<3x-1/-2<91/100

Answer 1

\[\frac{9}{10}<\frac{3x-1}{-2}<\frac{91}{100}\]
Is this your question?

Answer 2

yes

Answer 3

You must solve each side separately.\[.9 < \frac {3x - 1}{-2}\]\[\frac {3x - 1}{-2} < .91\]Then combine the interval solution for x.

Answer 4

Multiply each side by -2, reversing the inequality signs:
\[\frac{-18}{10}>3x-1>\frac{-182}{100}\]
Rewrite it with less than signs:
\[\frac{-91}{50}<3x-1<\frac{-9}{5}\]
Add 1 to both sides:
\[\frac{-41}{50}<3x<\frac{-4}{5}\]
Divide each side by 3:
\[\frac{-41}{150}<x<\frac{-4}{15}\]
Interval notation:
\[(-\frac{41}{50},-\frac{4}{15})\]

Answer 5

thank you