Question

when looking at this: 2 / (x+h-3)(x-3)
why is A=2, B=1, and C=-3 ?

Answer 1

the question does not make sense - where did A, B and C come from?

Answer 2

those are the answers

Answer 3

i wanna know how you get them

Answer 4

there must be more information in the question that you have missed out

Answer 5

i made the question

Answer 6

by looking at the first thing how do you get the A, B, and C?

Answer 7

sorry - I can't help here - it really makes no sense to me.

Answer 8

this was supposed to be a simpler question -_-

Answer 9

how would you find A, B, and C by looking at the first thing? (phrased better?)

Answer 10

hold on

Answer 11

If f(x) = x2 - 6x + 1, then f(1) = -4, f(2) = -7, f(3) = -8, .... p(x) = (x - h)q(x) + p(h); they give us the expression ... Find numbers a, b, c, and d such that f(x) ... and q integers having no common integral divisor greater that 1, then p must be an integral .

Answer 12

"2 is to 3 as 10 is to 15." Because 2 is two thirds of 3, just as 10 is two thirds of 15. ... c) x : y = 7 : 10. x is seven tenths of y. .... h) In a class of 40 pupils, 25 got a B.

Answer 13

huh?

Answer 14

For example: In a class of 40 pupils, 25 got a B.

Answer 15

In order to learn calculus, you have got to be able to do algebra. .... In the previous example, where h = 3, k = 5, and m = 2, this leads to a very quick solution: ... Suppose you had y = 2x - 1 as one equation and y = 0.4x + 3 as the other. ... Of course, a, b, and c need not be nice neat symbols, as I have here, but each might be .

Answer 16

start the power at 1 and increase by 1 each time, getting up to n. ... But how are we going to solve for A, B, and D. We cannot plug in numbers to ... If we did, we would see that A = 2, B = 2, C = 3, D = -4, E = -3, F = 0, G = 3, H = -3, and I = -2.

Answer 17

ur losing me... my brain is not as advanced as urs lol

Answer 18

k? then wat grade r u in

Answer 19

so i can simple it up

Answer 20

im in college but im terrible at math

Answer 21

k?

Answer 22

?