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OpenStudy (anonymous):
PLEASE HELP!!! He paddled for 4hrs with 4km/h current. On way back it took 8 hrs against current. Find speed of boat in still water.
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OpenStudy (anonymous):
Let the distance be X. Then (using distance = speed times time)) X = (u+4)4. On the way back, he will also travel a distance of X, but will be fighting the current so X=(u-4)8. Solve the equation for u: (u+4)4=(u-4)8 --> -4u = -16-32 --> u = 12.
OpenStudy (mertsj):
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