Question

Find all real solutions to equation:x^4/3-11x^2/3+24=0

Answer 1

solve
\[u^2-11u+24=0\] then replace u by
\[x^{\frac{2}{3}}\]

Answer 2

\[\large (\frac{x^4}{3-11}) (\frac{x^2}{3+24})=0 \text{ is this the question?} \]

Answer 3

once I factor, I get (u-8)(u-3)?

Answer 4

\[x^{\frac43}-11x^{\frac23}+24=0\]

Answer 5

\[\large x^{4/3}-11x^{2/3}+24=0??? \]

Answer 6

ohhhh

Answer 7

\[x^{4/3}-11x ^{2/3}+24=0\]

Answer 8

then what satellite said :)

Answer 9

yes

Answer 10

what does \[x ^{2/3}=8\] equal for x?

Answer 11

no, 3/2

Answer 12

that means \[\large \sqrt[3]{x^2}=8 \]

Answer 13

you raise both sides to the power 3, that will clear the cube root on the x and make 8^3=512 then you find the square root of 512, and that is your x :)