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solve using interval notation. 3(t-1)-4(t+1)
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First distribute
\[3t-3-4t-4\le-12\]
Combine like terms
\[-t-7\le-12\]
add 7
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divide by the negative
don't forget to flip the sign to greater than or equal to
So you get t greater than or equal to 5
Interval notation would be bracket -infinite, 5 bracket
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