Question

A baseball thrown straight up into the air has height s(t)=6+48t-16t^2 feet after t seconds.Its velocity at time t is given by v(t)=48-32t. At what time(s) will the ball be 38 ft above the ground?

Answer 1

plug in s(t) = 38
solve for t using quadratic formula

Answer 2

can you show me how to

Answer 3

set it equal to 0
16t^2 -48t +32 = 0
divide by 16
t^2 -3t +2 = 0
(t-2)(t-1) = 0
t = 1,2

haha it factors so no quadratic formula needed