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Mathematics 14 Online
OpenStudy (anonymous):

solve 3x^2 + 12x +8=0

OpenStudy (anonymous):

help me please

OpenStudy (anonymous):

i know that but i got the wrong answer

OpenStudy (dumbcow):

a = 3 b = 12 c = 8 \[x=\frac{-12 \pm \sqrt{144-96}}{6} = \frac{-12 \pm 4\sqrt{3}}{6} = \frac{-6 \pm 2\sqrt{3}}{3}\]

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