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solve 3x^2 + 12x +8=0
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help me please
use quadratic formula http://upload.wikimedia.org/wikipedia/en/math/8/e/4/8e4fef5352eb498b3534af481c8c4fd4.png
i know that but i got the wrong answer
a = 3 b = 12 c = 8 \[x=\frac{-12 \pm \sqrt{144-96}}{6} = \frac{-12 \pm 4\sqrt{3}}{6} = \frac{-6 \pm 2\sqrt{3}}{3}\]
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