Question

solve with steps. solve using the discriminant formula 2t^2 + 1 =7t

Answer 1

\[2t ^{2}-7t+1=0\]
\[d=b ^{2}\pm \sqrt{b ^{2}-4ac}/2a\]
Use the formula and find the answer?
2=a
b=-7
c=1

Answer 2

The discriminant is b^2-4ac, it will tell you if the zeros are real or complex
The quadratic formula is:
\[t=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]