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How do I simplify the fifth sqrt of 1/32 ?
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1/2
\[\sqrt[5]{1 \over 32} = {1 \over \sqrt[5]{32}} = {1 \over 2}\]since \(2^5 = 32\)
1 = 1*1*1*1*1 32 = 2*2*2*2*2 so 1/2
Awesome! Thanks everyone!
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One more question... it was actually \[-\sqrt[5]{1-32}\] so does that make the answer - 1/2 ?
If that was the actual equation, it should be very close to, but not exactly \(-{1 \over 2}\)
Great, thank you :)
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