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U has degree 5, zeros 1 2 , −5, and −i, and leading coefficient 4; the zero −5 has multiplicity 2.
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Are we looking for the equation of U(x)?
yes
If U(x) has degree 5, that means its has 5 roots. Roots listed in the problem are the following: 1, 2, -5, -5 (double root), -i, and then its conjugate i has to be a root if the function has real coefficients. Well, that's a total of 6 roots so I don't know how that can happen.
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