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Mathematics 12 Online
OpenStudy (anonymous):

average rate of change for the equation y=x^2-x-12,0lexle2?

OpenStudy (anonymous):

\[y=x^{2}-x-12,0\le x \le2\]

OpenStudy (anonymous):

You want the difference quotient here

OpenStudy (anonymous):

\[\frac{f(x+h)-f(x)}{h}\]

OpenStudy (anonymous):

\[\frac{f(2)-f(0)}{2-0}\]

OpenStudy (anonymous):

yes but what is the average rate of change for this equation

OpenStudy (anonymous):

step by step instructions please i have an exam tomorrow

OpenStudy (anonymous):

That will give you the average rate of change. It's called the difference quotient.

OpenStudy (anonymous):

okay so i just solve that equation you gave me

OpenStudy (anonymous):

yes, a nd remember the equation for a difference quotient

OpenStudy (anonymous):

You can get the answer for any interval if you evaluate the difference quotient.

OpenStudy (anonymous):

in terms of x and h

OpenStudy (anonymous):

appreciate it

OpenStudy (anonymous):

no problem

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