Question

How do you solve nx^2-n-2=0? I keep getting n=2,-1. Can someone explain to me why this isn't right?

Answer 1

Do you mean n^2 - n - 2 = 0

Answer 2

yeah lol

Answer 3

n^2 - n - 2 = 0
n^2-2n+1n - 2 = 0
n(n-2)+1(n-2) = 0
(n+1)(n-2) = 0
n = -1, 2

Answer 4

Your answer appears to be correct.

Answer 5

see that's what i got too but my teachers answer on her lecture video is n=2,1

Answer 6

thanks for your reply i just needed someone to get my same answer = ]