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for the function f(x)=(8-2x)^2, find f^-1,determine whether f^-1 is a function HELP PLEASE :))
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inverse is |dw:1329334385996:dw|
To find the inverse of a function swap the positions of x and y. Pretend that F(x) is y, so y = (8 - 2x)^2 If we swap them it becomes. x = (8 - 2y)^2 Now we solve for y sqrt(x) = 8 - 2y sqrt(x) - 8 = -2y y = (8 - sqrt(x)) / 2
is it a function?
Yes, it is a function.
As long as x is never negative, however
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thank you SO much, i really do appreciate the help (:
No problem XD.
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