Question

Related rates problem: If a snowball melts so that its surface area decreases at a rate of 1cm^2/min, find the rate at which the diameter decreases when the diameter is 10cm.

Answer 1

how about this
let D= diameter (cm), S= surface area, t= time (minutes)
\[\frac{dD}{dt}= \frac{dD}{dS}\frac{dS}{dt}\]
use
\[ S= \pi D^2 \]