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Solve the system 3x - 5y = 8 and 4x - 7y = 10.
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solve one of the equations for x and then plug that into the other equation
x = (8/3) + (5/3)y plug that into 4((8/3) + (5/3)y) - 7y =10
yeah... X=6 Y=2
3x - 5y = 8 4x-7y = 10 3x - 8 = 5y 4x - 10 = 7y y = (3x-8)/5 y = (4x-10)/7 y = y 7(3x-8) = 5(4x-10) 21x - 56 = 20x - 50 21x - 20 = 56 - 50 x = 6 y = 2
Thanks, but I think you're supposed to write it in the form of exponents.
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Oh, nevermind. I figured it out. Thanks!
You mean x,y = (6,2)
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