The surface area "S" of a right prism is given by
S=2B+Ph
where "B" is the area of the base, "P" is the perimeter of the base, and "h" is the height of the prism.
Solve for "h"?

Question

The surface area  "S" of a right prism is given by 
S=2B+Ph
where "B" is the area of the base, "P" is the perimeter of the base, and "h" is the height of the prism. 
Solve for "h"?

anonymous · Answer

S = 2B + Ph
S - 2B = Ph
(S-2B/P = h

anonymous · Answer

S=2B+Ph
S-2B=Ph
(S-2B)/P=h
then just put the values and get the answer if you have them.

anonymous · Answer

(S-2B)/P

i mean

basically, move all terms to one side and try to get p all by its lonesome

anonymous · Answer

try to get h* man im not with it