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Calculus Help! Evaluate the derivative. d/dx∫tsin(6t)dt where the lower limit is 2 and upper limit is x^3
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\[(d/dx)\int\limits_{2}^{x^3}tsin(6t)dt\]
yea
3x^2 sin (6x)
is that equal to 6x^3sin(6x^3)?
Maybe find the integral first, insert those boundaries in F(b) - F(a), and then find that derivative?
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You plug in the x^3 into the function, then multiply by the derivative of x^3
yea,that's what i did
Yeah, I'm not sure what I was doing...
oh,thanks a lot though
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