Question

5by^3/8a^3d-w^2/2ab^2

Answer 1

no more trig?

Answer 2

my assignments go back and forth because im on bed rest and I've missed so much

Answer 3

common denominator is
\[8a^3b^2d\] if i am reading the question correctly

Answer 4

\[\frac{5by^3}{8a^3d}-\frac{w^2}{2ab^2}\]right?

Answer 5

exactly.

Answer 6

so you have to multiply the first one top and bottom by
\[4b^2\] and the second one top and bottom by
\[4a^2d\]

Answer 7

this is a pain

Answer 8

\[\frac{5by^3}{8a^3d}-\frac{w^2}{2ab^2}\]
i am sorry i messed up

Answer 9

yeah your telling me.. ive been doing this one assignment for 5 hours

Answer 10

let me just write what you need to do

Answer 11

okay:)

Answer 12

\[\frac{5by^3b^2}{8a^3b^2d}-\frac{8a^2dw^2}{8a^3b^2d}\]
\[

Answer 13

\[\frac{5b^3y^3-8a^2d^2w^2}{8a^3b^2d}\]

Answer 14

how the flipper does that even simplify with all the variables not being the same for the numerator?