Question

wdf is gbasallote 1 Medal Given
x^2 - 4x +(4/2)^2 = -2 +(4/2)^2
4/2 ^2 = 4

so...
x^2 - 4x + 4 =-2 + 4
x^2 - 4x +4 = 2
(x-2)^2 = 2
x-2 = sqrt 2

x = 2 plus/minus sqrt 2 wdf is sqrt 2

Answer 1

completing the square...

ax^2 + bx + c = 0

ax^2 + bx + (b/2)^2 = -c + (b/2)^2

which part did you not get?

Answer 2

sqrt 2

Answer 3

what does that mean

Answer 4

(x-2)^2 = 2

you need to find x but your x is in a binomial which is squared. so first you need to get rid of it. to do that, you need to get the sqrt of (x-2)^2..which is x-2...since you square rooted the left hand side, you must do so with the right. which gives you sqrt 2

Answer 5

wdf is sqrt mean?!?!?

Answer 6

oh wait, square root?

Answer 7

yes

Answer 8

so the final answer is... ?

Answer 9

the anssswer iss...?