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please solve equation:)
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\[-8/x-2+1-2x/x\]
Put brackets.
i am going to make a guess that this is \[\frac{-8}{x-2}+\frac{1-2x}{x}\] am i close?
yes you're right:)
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wait the first equation the negative is on the outside not with 8
\[\frac{-8}{x-2}+\frac{1-2x}{x}\] \[\frac{-8x+(x-2)(1-2x)}{x(x-2)}\]
ok makes no difference
then algebra in the numerator
multiply out, combine like terms and you should get \[\frac{-2 x^2-3 x-2}{x(x-2)}\]
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man you got a lot of work to do!
HAHA i know.. :/
when are they due?
tomorrow unfortunately.
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