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Plaese solve exponential equation: 4 over 9 exponent of C+3 = 3 over 2 exponent of C+9
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How about writing that in a mathematical notation?
\[\left(\begin{matrix}4 \over\ 9\end{matrix}\right)^C+^3 = \left(\begin{matrix}3 \over\ 2\end{matrix}\right)^C+^9\]
c = -5
WHAT!! How did u get that??
Can you explain please.
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Do you know logs?
yes
That's aweome. \[\log(4/9)^{C+3} = \log(3/2)^{C+9}\]
Then, \[(C+3) \log(4/9) = (C+9) \log (3/2)\]
Then, \[(C+3)/(C+9) = \log(3/2) / \log(4/9)\]
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That would make it equal -7
\[(C+3)/(C+9)=-0.5\]
oh k i got it thank you.
Cool, solve for C.
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