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y=x^2-2. What is Δ Y?
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Δ Y= \(dy\) let's find Δ y/Δx when Δ x--->0 Δ y/Δx ---> dy/dx let's find dy/dx =2x dy=2x dx so Δ y=2xΔx
That wasn't one of the answers.. I chose something longer like [(x-Δx)^2-(something) (x^2-2)]
yeah it can be like this also y=x^2-2 (y+Δ y)=(x+Δx)^2-2 subtracting the two , we get Δy= (x+Δx)^2-(x^2)
Shoot, got that one wrong.
are you writing a test?
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Nope, I just took my calc test and i'm checking the ones i wasn't sure about!
okay :) do it well next time:)
thanks!
Do you know if there is a function with 5 horizontal asymptotes? this was another t/f question
We'd have to check options, can't tell like this . Maybe the function is piece wise defined
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