Question

solve for x under the assumption that x<0x-3/x<-2 ?

Answer 1

\[x-3/x<-2\]

Answer 2

x-3<-2x [when x>0]
x+2x<3
x<3 so 0<x<3;

again if x<0 then
x-3>-2x
x+2x>3
x>1 it contradicts the assumption x<0 so only possible solution of x is 0<x<1