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Evaluate the limit lim x->0 (x+8)^(1/3) -2 ___________ x
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This? \[\lim_{x \rightarrow 0} \frac{(x+8)^{1/3}-2}{x}\]
Yes i was just going to type that, sorry. I've been reviewing limits and I keep screwing this one up.
You can use l'hospital's rule
\[\lim_{x \rightarrow 0} \frac{(x+8)^{1/3}-2}{x} APPLY L'HOSPITAL RULE.. \lim_{x \rightarrow 0} \frac{1/3(x+8)^{-2/3}}{1} =1/12 \]
until now I had never heard of l'hostpital's rule. But I just wiki'd it. Interesting. Thank you guys! Much appreciated :)
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