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Mathematics 10 Online
OpenStudy (pokemon23):

here is my second question about factoring

OpenStudy (pokemon23):

z^3-z

OpenStudy (pokemon23):

so i got

OpenStudy (pokemon23):

z(z^2-1)

hero (hero):

z^3-z = z(z^2-1) = z(z+1)(z-1)

hero (hero):

You have to factor completely. I'm sure you're familiar enough with difference of squares

OpenStudy (pokemon23):

yes .............................

hero (hero):

I'm on skype by the way

OpenStudy (pokemon23):

wanna help me?

OpenStudy (pokemon23):

wanna chat in skype Hero?

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