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OpenStudy (pokemon23):
here is my second question about factoring
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OpenStudy (pokemon23):
z^3-z
OpenStudy (pokemon23):
so i got
OpenStudy (pokemon23):
z(z^2-1)
hero (hero):
z^3-z = z(z^2-1) = z(z+1)(z-1)
hero (hero):
You have to factor completely. I'm sure you're familiar enough with difference of squares
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OpenStudy (pokemon23):
yes .............................
hero (hero):
I'm on skype by the way
OpenStudy (pokemon23):
wanna help me?
OpenStudy (pokemon23):
wanna chat in skype Hero?
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