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solve for x over the inverval [0, 2π) 1) cos²x+ 2cosx-3 =0 2) (tanx-1) (cosx+1) =0 3)3sec3x-2√3 =0
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4*cos(2x)*sin(2x) = 1 First we will divide by 2 . ==> 2cos(2x)*sin(2x) = 1/2................(1)
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