Question

New question guys last one of the night....yes you wanna do it....just go on ahead and do it...you know you wanna.....
A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 24sq feet. find the lengths of the sides and the posters of the signs.

Answer 1

let x be the sides of the poster, so area of poster is x^2
then x+2 is the length of the sides of the sign, so area of sign is (x+2)^2
the different in their areas is (x+2)^2 - x^2 = x^2 + 4x + 4 - x^2 = 4x+4
so 4x+4 = 24, solve for x