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OpenStudy (anonymous):
(x+2)^2-x^2=24 solve for x
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myininaya (myininaya):
Multiply (x+2)(x+2)\[=x^2+2x+2x+4=x^2+4x+4\] So we have \[x^2+4x+4-x^2=24\] combine like terms! :)
myininaya (myininaya):
\[4x+4=24 \text{ since } x^2-x^2=0\]
OpenStudy (anonymous):
thanxxxxx
OpenStudy (anonymous):
myininaya sorry but where did you get the x for the 4?
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