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The box contains 8 balls: 4 red, 1 green, 3 blue. Two balls are drawn at random, one after the other without replacement. What is the probability that the first ball was blue, given that second was red_________________?
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Add all the numbers and put 3 over that number
Say what?
3/16
add all which numbers?
3/16 was not correct
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Gummy, its 8 balls in total, not 8, 4, 1, and 3. So its 3/7. Essentially its Probability of Desired result / Total Results. Since a red ball was already picked, you subtract one from total results.
Thank you so much Sulieman
3/14
3/7 is correct
you sure about that?
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