Question

The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 3.5 per week. Find the probability of the following event.

a) one accident today

Answer 1

haha i forgot what the Poisson distribution looks like...hold on a sec while i look it up

Answer 2

ok given mean is 3.5/week which is 0.5/day
\[P(k)= \frac{(0.5)^{k}e^{-0.5}}{k!}\]
where k=1
P(1) = 0.30327