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Mathematics 20 Online
OpenStudy (anonymous):

Find the derivative

OpenStudy (anonymous):

\[f(x)=\sin^2(\sqrt{x})\]

OpenStudy (anonymous):

\[f(x)=\sqrt{x}sinx\]

OpenStudy (anonymous):

\[\frac {\sin({\sqrt x})\cos({\sqrt x})}{\sqrt x}\]

OpenStudy (anonymous):

\[=\frac{\sin (2\sqrt x)}{2 \sqrt x}\]

OpenStudy (anonymous):

for f(x)=sqrt(x)sin(x) the derivative is \[\sqrt x \cos(x)+\frac {\sin (x)}{2\sqrt x}\]

OpenStudy (anonymous):

hope you got it properly...

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