Question

if the slope of the curve x^2+y^2 = 25 is -(3/4) at point (x,y) find the value of x and y.

a. 3 and 4

b. 3 and 4.2

c. 2 and 3

d. 3.5 and 4

Answer 1

Find dy/dx. 2x+2y(dy/dx)=0;
dy/dx = -(x/y).
So -(x/y)=-(3/4)
4x-3y=0;
x=(3/4)y.
Put this value of x in the curve equation and get x. Then find y.0

Answer 2

is that y.0? =0 then the answer is 3 and 4 because y =0 then x = 3/4