find the second derivatives of y= x^3(2x+4)^2

a. 2x+4

b. x^3(2x+80)

c. x^2(80x+192)

d. x^2(20x+60)

Question

find the second derivatives of y= x^3(2x+4)^2

a. 2x+4

b. x^3(2x+80)

c. x^2(80x+192)

d. x^2(20x+60)

anonymous · Answer

i find it x^2(4x+8)

anonymous · Answer

But the answer you chose it's not listed on the multiple choices.

anonymous · Answer

yes thats y i think the answer is e for error LOL

anonymous · Answer

do you find it the same with me?

anonymous · Answer

I feel like it's A or B.

anonymous · Answer

letter a has a chance w8 i check it

anonymous · Answer

ok

bahrom7893 · Answer

product rule... twice.. what a pain (go on wolf)

bahrom7893 · Answer

http://www.wolframalpha.com/input/?i=%28Differentiate%284x^2*%285x^2%2B16x%2B12%29%29

bahrom7893 · Answer

woahh wait...

bahrom7893 · Answer

meh.. ill just solve it by hand

anonymous · Answer

theres a 20x in your wolf i see the light from letter d XD

bahrom7893 · Answer

still simplifyin the 2nd derivative....

bahrom7893 · Answer

i cant factor it into any of the forms..., neither can wolframalpha :/ are u sure the question's correct?

anonymous · Answer

so the real answer is finally shown letter E =error  thank u bah

bahrom7893 · Answer

lol np.. well at least my answer was right.. haha
16x(5x^2+12x+6), wolf confirmed it.

anonymous · Answer

so you get the 2nd derivati easy enough..can i have a tip on derivative..do you think i need to memorize all the formula so i can get it easy on quiz? i have quiz on derivative tommorow

anonymous · Answer

$$(fg)'=f'g+g'f$$ so in this case you would use 
$$f(x)=x^2,f'(x)=2x$$
$$g(x)=(2x+4)^2,g'(x)=2(2x+4)\times 2=4(2x+4)=8x+16$$

anonymous · Answer

oww the f o g so your answer to is letter e? XD