Question

I need help with this

2^(Log_2_(3) - Log_2_(5))

Answer 1

Is this your question
\[2^{\log_{2} 3-\log_{2}5}\]?

Answer 2

yes

Answer 3

we know
\[ \log_{a} b -\log_{a} c= \log_{a} {\frac{b}{c}}\]
so her we'll get
\[ 2^{log_{2} 3-log_{2} 5}= 2^{log_{2} \frac{3}{5}}\]
now we know that
\[a^{\log_{a} b}= b\]
so we get
\[2^{log_{2} \frac{3}{5}}= \frac{3}{5}\]

Answer 4

ah ah!