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If sin y°=and tan y°=,what is the value of cos y°? cos y° =6/b cos y°= 6a cos y°= 6b cos y° =b/6 i do not get this soh cah toah or whatever
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SOH CAH TOA my fav acronym in math :) i think you are missing info sin y = ?
sorry it didn't load. If sin y°=a/6and tan y°=a/b,what is the value of cos y°?
for this question, just use the fact that tan = sin/cos --> a/b = (a/6)/cos --> cos = (a/6)/(a/b) = a/6 * b/a = b/6
|dw:1329504334783:dw| sin y = opp/hyp = a/6 cos y = adj/hyp = b/6 tan y = opp/adj = a/b
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