Question

Let logb A=3; logb C=2; logb D=5 What is the value of logb A^5C^2/D^6?

Answer 1

lobg A^5 = 5logb A = 15
logb C^2 = 2 logb C = 4
logb D^6 = 6 logb D = 30

can u continue from here - this is an exercise in applying laws of logs

Answer 2

logb A^5 C^2 / D^6 = log A^5 + logb C^2 - logb D^6

so plug in the above values and you've got it