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Mathematics 15 Online
OpenStudy (anonymous):

Factor by grouping. 3n3 – 12n² + 2n – 8? (3n2 – 2)(n + 4) (3n2 + 2)(n – 4) (n + 2)(3n – 4) 3(n³ –4n²) + 2n – 8

OpenStudy (nenadmatematika):

3n^2(n-4)+2(n-4)=(n-4)(3n^2+2) so it's the second choice

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