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OpenStudy (anonymous):
Factor completely. 6a³ – 10a² + 3a – 5? Plz show work so i can see how to do it
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OpenStudy (nenadmatematika):
=2a^2(3a-5)+(3a-5)=(3a-5)(2a^2+1)
OpenStudy (anonymous):
3a ( 2a^2 + 1) - 5 ( 2a^2 + 1) = (2a^2 + 1) ( 3a - 5)
OpenStudy (anonymous):
Group the 1st and 3rd terms together then group the second and constant together => group the common result
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