Question

the circle given by x^2+y^2+4x-10=0 can be written in standard form like this: (x-h)^2+y^2=14 what is the value of h

Answer 1

h=-2

Answer 2

h = -2

Answer 3

(x+2)^2+y^2=10+4
(x+2)^2+y^2=14 so the value of h is -2
is look like +2 but you always negate the value in bracket thus why is h=-2