Question

Frogs have been breeding like flies at the Enormous State University (ESU) campus! Each year, the pledge class of the Epsilon Delta fraternity is instructed to tag all the frogs residing on the ESU campus. Two years ago (t = 0) they managed to tag all 54,000 of them (with little Epsilon Delta Fraternity tags). This year's pledge class discovered that all the tags had all fallen off, and they wound up tagging a total of 86,400 frogs.
(a) Find an exponential model for the frog population.

Answer 1

86400=54000e^k(2)

Answer 2

Solve for k

Answer 3

so i got 1.6=e^k(2)

Answer 4

then ln1.6=e^k(2)(ln)

Answer 5

does ln and e cancel out?

Answer 6

\[\ln 1.6=2k \ln e\]

Answer 7

ln 1.6 = 2k

Answer 8

1.6/2 = k

Answer 9

They don't cancel out.

Answer 10

ln e = 1

Answer 11

\[\ln _{e}e=1\]

Answer 12

Yes.

Answer 13

.08 = k

Answer 14

\[\frac{\ln 1.6}{2}=k\]

Answer 15

k=.235

Answer 16

ooo forgot about ln

Answer 17

\[\ln 1.6 = 2k\]

Answer 18

what do i do with k=.235 , can i plug that in so i can make the equation now?

Answer 19

y=Ab^x

Answer 20

\[A=a _{0}e ^{.235t}\]

Answer 21

i plugged in f(t)=54000e^.235t

Answer 22

but its not correct

Answer 23

Then leave out the 54000

Answer 24

so just f(t)=e^.235t?

Answer 25

Did you see what I wrote?

Answer 26

A=a0e.235t

Answer 27

Or it is possible that they want more or fewer significant digits on the constant.

Answer 28

is the zero supposed to be in the equation you showed me?

Answer 29

\[A _{o}\]
indicates the initial amount. Use anything you please for that.

Answer 30

Probably you should use the same variables that your book or instructor has been using.