Question

An astronaut on a strange planet finds that she can jump a maximum range of 15m with an initial speed of 3m/s. What is the free fall acceleration on the planet?

Answer 1

0=3^2-2*a*15
9=30a
a=9/30=.3m/s^2
that is the acceleration

Answer 2

third law of motion:
v^2=u^2-2as where a acceleration and s the distance u initial velocity and v final velocity