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Simplify the following fraction: ((1/x)-x)/((1/x)+1) I'll draw it too
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(-x+1/x)/[1+1/x]
\[\frac{\frac{1}{x}-x}{\frac{1}{x}+1}\]
(1 - x^2 ) / (x + 1) = 1-x
Is that it?
[[-x^2+1]/2]/[x+1]/2
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1-x^2/1+x
final ans
Multiply numerator and denominator by x and get: \[\frac{1-x ^{2}}{1+x}=\frac{(1-x)(1+x)}{1+x}=1-x\]
|dw:1329528593968:dw|
[1-x][1+x]/[1+x]=1-x
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|dw:1329529210193:dw|
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