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if i were to provide all the possible rational zeros to f(x) = 9x^4 – 17x^3 + 2x^2 – 3x + 33 would i get : 1/9, 1/3, 11/3 ? when simplified
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make a fraction where numerator is all divisors of 33, denominator is all divisors of 9 there are a lot, and don't forget \[\pm\]
\[\pm1,\pm3, \pm11, \pm 33,\pm \frac{1}{3},\pm\frac{11}{3},\pm\frac{1}{9},\pm\frac{11}{9}\] maybe even some i missed
oh so i wouldnt simplify the fraction 33/9?
yes
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