Question

\[ \mathcal{L} \{ erfc(\sqrt t) \}=\]

Answer 1

\[ \mathcal{L} \{ erfc(\sqrt t) \}\]\[ =\mathcal{L} \{ {2\over√π}\int_{√t}^∞e^{-u^2}du \}\]

Answer 2

\[ = {2\over√π} \int_0^∞[ \int_{√t}^∞e^{-u^2}du] e^{-st}dt\]