Ask your own question, for FREE!
Chemistry 15 Online
OpenStudy (anonymous):

A 50.0-mL volume of 0.15M HBr is titrated with 0.25M KOH. Calculate the pH after the addition of 18.00mL of KOH

OpenStudy (anonymous):

meq of HBr=50*0.15=7.5 meq of KOH=0.25*18=4.5 meq of HBr left=3. conc=3*10^-3 pH= 3-log 3=3-0.477=2.523

OpenStudy (anonymous):

thanks..but could you explain to me please?meq = Molarity at equilibrium?

OpenStudy (anonymous):

meq=milli equivalents. which in this case is just milli moles.

OpenStudy (anonymous):

oh I see...that is why you don't write m with capital letter? but,the real answer is pH= 1.36

OpenStudy (anonymous):

Ah ok i got my mistake i took the concentration wrong :) moles=3*10^-3 volume=68. so conc=3*10^-3/68. Now take -log of that.

OpenStudy (anonymous):

oh..thanks .I figured it out :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
AsianPanda08: What should i eat for dinner tonight? I can't choose
46 minutes ago 51 Replies 2 Medals
Nina001: Trying 2 figure out what is the square root of 8746685
1 hour ago 23 Replies 2 Medals
SnowyBreaks: Is it bad to lose 3.8 pounds in less than 2 days?
45 minutes ago 42 Replies 0 Medals
kaelynw: tried a lil smt, the arm is off but i like the other stuff
4 hours ago 8 Replies 2 Medals
laylasnii13: Who wanna write or make a song with me???
4 hours ago 8 Replies 0 Medals
kaelynw: art igg
12 hours ago 13 Replies 2 Medals
XShawtyX: Art
1 day ago 6 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!