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OpenStudy (sette):
what is the product of (3x^2/x+2)/(5x^2-20/30x^3) ? simplify completely. Algebra 1 Honors.
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OpenStudy (anonymous):
\[\frac{3x^2}{x+2} * \frac{5x^2-20}{30x^3}\]
OpenStudy (anonymous):
right?
OpenStudy (sette):
yes thats the equation.
OpenStudy (anonymous):
5x^2 - 20 can be factored as 5(x^2-4) = 5(x+2)(x-2)
razor99 (razor99):
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razor99 (razor99):
thats the answer
OpenStudy (anonymous):
(x+2) can be cancelled out and 3x^2 can also be cancelled out
so you are left with \\[\frac{5x-10}{10x}\]
OpenStudy (sette):
3x^2 can be canceled because you simplified it with 30x^3?
OpenStudy (anonymous):
yes
OpenStudy (sette):
oh okay Thank YOu .
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razor99 (razor99):
hey sette check my answer
OpenStudy (radar):
\[5(x-2)\over10x\]\[x-2\over2x\]
OpenStudy (sette):
razor i dont know how you got that .
OpenStudy (radar):
I am assuming moneybird was correct and further simplified the final answer.
OpenStudy (radar):
As shown I removed the common factor and placed it outside parenthesis. then divided numerator and denominator by the 5. getting the final answer
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OpenStudy (sette):
Yes Thank You. He is correct and your simplification was correct.
OpenStudy (radar):
You're welcome and good luck with these.
OpenStudy (anonymous):
(3x^2/x+2)/(5x^2-20/30x^3)
(3x^2/x+2) * ( 30x^3/ (5x^2-20)
= 90 x^3/ 5 ( x^3 - 8)
= 18 x^3/ ( x^3 - 8)
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