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factor fully: 2xy+4x+3y+6 9x^2-24x+16
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sorry those are supposed to be seperate: \[2xy+4x+3y+6\] \[9x^{2}-24x+16\]
2x(y+2)+3(y+2) (y+2)(2x+3)
9x^2-12x-12x+16 Use the same principle
2xy+4x+3y+6 = 2x(y +2) + 3(y +2) = (2x +3) (y + 2)
9x2−24x+16 = ( 3x - 4 )^2 = 0 => x = 4/3
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