help with equations ....assume that there is a rectangular yard ( L& W in meters) and there is a rectangular house which has to be placed in this yard ( L& W in meters) . how can i compute the time (in minutes) required to cut the lawn around the trees. (assume that the mowing rate is in square meters per minutes)

Question

help with equations ....assume that there is a rectangular yard ( L& W  in meters) and there is a rectangular house which has to be placed in this yard ( L& W  in meters) . how can i compute the time (in minutes) required to cut the lawn around the trees. (assume that the mowing rate is in square meters per minutes)

mertsj · Answer

Since the dimensions of the yard and the house are the same, there will be no yard to cut.

anonymous · Answer

no they are not the same

anonymous · Answer

it is a code problem for computer science

mertsj · Answer

It says in your problem that they both have dimensions L and W so according to you they are the same.

anonymous · Answer

So Area of  the yard > Area of the house
=> Cutting area = area of yard - area of house

anonymous · Answer

no i mean that the dimensions L and W are in meters

anonymous · Answer

ok what about the equation of the time

anonymous · Answer

t = Area/ velocity
because v unit as you said m^2/min

anonymous · Answer

ok got it thanks

anonymous · Answer

In case they ask for second, then min * 60 = t sec.

anonymous · Answer

alright thanks

anonymous · Answer

You're welcome!