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since e^0=1 what is e^1=
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just e^1 or 2.72
actual am solving a calculus problem) of derivative
solving for y,inother to get the equation of a tangent line
y=x^3 e^x when x=1
if i substitute the 1 into x my answer comes out as "e"
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ok so y' wil give you the slope y' = 3x^2*e^x + x^3*e^x x=1 y'(1) = 3e +e = 4e
ok thanks
just wanted to be sure if i were doing the right thing
no problem :)
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